((3x+6)/(5x^2))((x)/(x^2-4))

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Solution for ((3x+6)/(5x^2))((x)/(x^2-4)) equation: 


D( x )

x^2-4 = 0

5*x^2 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

5*x^2 = 0

5*x^2 = 0

5*x^2 = 0 // : 5

x^2 = 0

x = 0

x in (-oo:-2) U (-2:0) U (0:2) U (2:+oo)

((3*x+6)/(5*x^2))*(x/(x^2-4)) = 0

(x*(3*x+6))/(5*x^2*(x^2-4)) = 0

( 3*x+6 )

3*x+6 = 0 // - 6

3*x = -6 // : 3

x = -6/3

x = -2

( x )

x = 0

x in { -2} 

x in { 0} 

x belongs to the empty set

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